Need help with a math problem I've been stuck on for a while. What's the answer to: Find all solutions of tan^3X = tanX (X = theta) on [0,2pi). I got as far as simplifying it to: tanX(tan^2X-1) = 0 but am now stuck. Help?
I only know basic trigonometry so far, and I don't really understand the question. But, I can tell you that in a unit circle, the tangent of 2 pie = the coordinates (1,0) so here x would be 1/3. But that's all I can tell you really.
since tanx(tan^2x-1) = 0, then either: tanx = 0, or tan^2x-1 = 0 if you define a function over x, f(x) = tanx(tan^2x-1), then the solutions to the above two equations will give you the points where the function cuts through the x-axis (i.e. when f(x) = 0). So simply solve the values of X for each of the two equations and thats your answer.
