Anybody Here Good At Math? I Need Some Help.

Discussion in 'Lounge' started by Aussie, Oct 14, 2010.

  1. Aussie

    Aussie Well-Known Member

    Aug 11, 2010
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    School.
    I forgot everything from last year in 8th grade, I am now in integrated Algebra 1. I had all A's last year and now I have a D in this class. If anyone here is smart can you please show me some work on how to do these problems. No flaming, please:eek:

    1. -x + 4y - 7x +8y + (-3x) - 2y
    2. (2/3)(-2/5)(2/7)
     
  2. da shiz wiz 19

    da shiz wiz 19 Well-Known Member

    Sep 24, 2009
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    #2 da shiz wiz 19, Oct 14, 2010
    Last edited: Oct 14, 2010
    (2/3)(-2/5)(2/7) = (2*-2*2)/(3*5*7) = (-8/105)

    No thank you neccessary :rolleyes:

    EDIT: I would help if you told us what we're trying to solve for and what the fraction in 2 are.
     
  3. 270Kp

    270Kp Well-Known Member

    Oct 27, 2009
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    Beta-Tester
    USA
    Iz your life still perfect? :D

    Jk, wish I could help you but I haven't taken math since freshmen year.
     
  4. Aussie

    Aussie Well-Known Member

    Aug 11, 2010
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    School.
    No:(
     
  5. Spaztrigger

    Spaztrigger Well-Known Member

    Apr 4, 2010
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    Under your bed
    Isn't this distributive property? Then what you need to do is group all the x's together and all the y's together
     
  6. Booch138

    Booch138 Well-Known Member

    Apr 28, 2009
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    Data-Entry Operator
    Coolidge, AZ
    *head explodes*

    I u sed to be so good at math.

    Then I found pot.
     
  7. Rocketman919

    Rocketman919 Well-Known Member

    Aug 8, 2008
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    Cali-forn-i-a
    dude you've got to be kidding me if you can't do this. Looks like your perfect life is going to come crashing down because you are terrible in the one subject that is actually useful in life.
     
  8. Mew2468

    Mew2468 Well-Known Member

    Oct 20, 2008
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    Vancouver, BC
    -x + 4y - 7x + 8y + (-3x) - 2y =
    -x + 7x + -3x + 4y + 8y + -2y =
    3x + 10y


    I believe this is correct.
     
  9. LBG

    LBG Señor Member

    Apr 19, 2009
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    nada ilegal
    31.560499, -111.904128
    Don't say we didn't warn you ;)
     
  10. Somerandomdude

    Somerandomdude Well-Known Member

    May 31, 2009
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    Doing nothing of importance.
    Somewhere
    First we have a thread about how great his life was and how it would eventually crash, and now we have the actual downfall thread! Woohoo! :D
     
  11. da shiz wiz 19

    da shiz wiz 19 Well-Known Member

    Sep 24, 2009
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    No wonder his life was great...his homework involves adding, subtracting and multiplying.
     
  12. Somerandomdude

    Somerandomdude Well-Known Member

    May 31, 2009
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    Doing nothing of importance.
    Somewhere
    No kiddin man... I didn't actually take a look at it since it was solved by the time I checked this out, but it looked pretty easy.

    Ohhhh... he's gonna have a ton of fun going through Algebra 2... :D
     
  13. Electric_Shaman

    Electric_Shaman Well-Known Member

    Jul 22, 2009
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  14. LBG

    LBG Señor Member

    Apr 19, 2009
    7,471
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    nada ilegal
    31.560499, -111.904128
    [​IMG]
     
  15. sammysin

    sammysin Well-Known Member

    Feb 23, 2010
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    Government Official.
    Swansea, UK
    ROFL, love this.
     
  16. Electric_Shaman

    Electric_Shaman Well-Known Member

    Jul 22, 2009
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    [​IMG]
     
  17. doodlejumper

    doodlejumper Well-Known Member

    Jan 27, 2010
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    Stuck in traffic
    There IS a math class social group you know. ;)
     
  18. B34$T

    B34$T Well-Known Member

    Aug 10, 2009
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    I love doing derivatives!

    Ok so:
    Y= -x + 4y - 7x +8y + (-3x) - 2y
    Therefore
    y'= -1dx/dy + 4 -7dx/dy + 8 -3dx/dy- 2

    y'= -11dx/dy +10

    Derivative of #2 would just equal 0.

    Happy to help.
     
  19. da shiz wiz 19

    da shiz wiz 19 Well-Known Member

    Sep 24, 2009
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    #19 da shiz wiz 19, Oct 14, 2010
    Last edited: Oct 14, 2010
    lmfao.

    But you can't do that, silly. It would have to be implicit differentiation and you would have to make the y into y primes (ex: 4y -> 4y' not 4). Then solve for y prime like algebra. Or you could first solve for y in terms of x and then find the derivative.
     
  20. B34$T

    B34$T Well-Known Member

    Aug 10, 2009
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    You need to go back to math class because you need to freshen up on your power rule.

    here is an example:
    Derivative of 4x^3
    4(3x^2)
    12x^2

    Because 4y is really 4y^1
    The power rule makes it 4(1y^0)
    Anything to the power of 0(except 0) is equal to 1.
    4*1*1=4
     

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