I forgot everything from last year in 8th grade, I am now in integrated Algebra 1. I had all A's last year and now I have a D in this class. If anyone here is smart can you please show me some work on how to do these problems. No flaming, please 1. -x + 4y - 7x +8y + (-3x) - 2y 2. (2/3)(-2/5)(2/7)
(2/3)(-2/5)(2/7) = (2*-2*2)/(3*5*7) = (-8/105) No thank you neccessary EDIT: I would help if you told us what we're trying to solve for and what the fraction in 2 are.
Isn't this distributive property? Then what you need to do is group all the x's together and all the y's together
dude you've got to be kidding me if you can't do this. Looks like your perfect life is going to come crashing down because you are terrible in the one subject that is actually useful in life.
First we have a thread about how great his life was and how it would eventually crash, and now we have the actual downfall thread! Woohoo!
No kiddin man... I didn't actually take a look at it since it was solved by the time I checked this out, but it looked pretty easy. Ohhhh... he's gonna have a ton of fun going through Algebra 2...
I love doing derivatives! Ok so: Y= -x + 4y - 7x +8y + (-3x) - 2y Therefore y'= -1dx/dy + 4 -7dx/dy + 8 -3dx/dy- 2 y'= -11dx/dy +10 Derivative of #2 would just equal 0. Happy to help.
lmfao. But you can't do that, silly. It would have to be implicit differentiation and you would have to make the y into y primes (ex: 4y -> 4y' not 4). Then solve for y prime like algebra. Or you could first solve for y in terms of x and then find the derivative.
You need to go back to math class because you need to freshen up on your power rule. here is an example: Derivative of 4x^3 4(3x^2) 12x^2 Because 4y is really 4y^1 The power rule makes it 4(1y^0) Anything to the power of 0(except 0) is equal to 1. 4*1*1=4
